for takrorlash operatori

• oldingi darslarimizda while operatori bilan ishladik

• for eng ko’p ishlatiladi

• asosan ketma-ketlikdan qiymatlarni birma-bir olib berish orqali ishlaydi

• bir necha xil sintaksisga ega

Sodda namunalar

fruits = ["apple", "banana", "cherry"]
for x in fruits:
  print(x)

apple
banana
cherry

for x in "banana":
  print(x)

b
a
n
a
n
a

# Iterating over dictionary
print("Dictionary Iteration")

d = dict()

d['xyz'] = 123
d['abc'] = 345
for i in d:
    print("% s % d" % (i, d[i]))

Dictionary Iteration
xyz  123
abc  345

t = ((1, 2), (3, 4), (5, 6))
for a, b in t:
    print(a, b)

1 2
3 4
5 6

range() funksiyasi

• 3 ta parameterdan iborat:

• start - qiymatning boshlanishi

• stop - qiymatning tugashi

• step - qadam

Namunalar

for x in range(6):
  print(x)

0
1
2
3
4
5

for x in range(2, 6):
  print(x)

2
3
4
5

for x in range(2, 30, 3):
  print(x)

2
5
8
11
14
17
20
23
26
29

for-else operatori

for x in range(6):
  print(x)
else:
  print("Finally finished!")

0
1
2
3
4
5
Finally finished!

Ichma-ich for operatori

adj = ["red", "big", "tasty"]
fruits = ["apple", "banana", "cherry"]

for x in adj:
  for y in fruits:
    print(x, y)

red apple
red banana
red cherry
big apple
big banana
big cherry
tasty apple
tasty banana
tasty cherry

break operatori

fruits = ["apple", "banana", "cherry"]
for x in fruits:
  print(x)
  if x == "banana":
    break

apple
banana

fruits = ["apple", "banana", "cherry"]
for x in fruits:
  if x == "banana":
    break
  print(x)

apple

for x in range(6):
  if x == 3: break
  print(x)
else:
  print("Finally finished!")

0
1
2

continue operatori

fruits = ["apple", "banana", "cherry"]
for x in fruits:
  if x == "banana":
    continue
  print(x)

apple
cherry

pass operatori

for x in range(10):
  pass

print(x)

9

enumerate() funksiyasi

• iterable - ketma-ketlik

• start - boshlanish indeksi

l1 = ["eat", "sleep", "repeat"]
s1 = "geek"

# creating enumerate objects
obj1 = enumerate(l1)
obj2 = enumerate(s1)

print ("Return type:", type(obj1))
print (list(enumerate(l1)))

# changing start index to 2 from 0
print (list(enumerate(s1, 2)))

Return type: <class 'enumerate'>
[(0, 'eat'), (1, 'sleep'), (2, 'repeat')]
[(2, 'g'), (3, 'e'), (4, 'e'), (5, 'k')]

l1 = ["eat", "sleep", "repeat"]

# printing the tuples in object directly
for ele in enumerate(l1):
    print (ele)

# changing index and printing separately
for count, ele in enumerate(l1, 100):
    print (count, ele)

# getting desired output from tuple
for count, ele in enumerate(l1):
    print(count)
    print(ele)

(0, 'eat')
(1, 'sleep')
(2, 'repeat')
100 eat
101 sleep
102 repeat
0
eat
1
sleep
2
repeat

fruits = ['apple', 'banana', 'cherry']
enum_fruits = enumerate(fruits)

next_element = next(enum_fruits)
print(f"Next Element: {next_element}")

Next Element: (0, 'apple')

zip() funksiyasi

fruits = ["apple", "banana", "cherry"]
colors = ["red", "yellow", "green"]
for fruit, color in zip(fruits, colors):
    print(fruit, "is", color)

apple is red
banana is yellow
cherry is green